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Hoyt Corkins Wins Bracelet No. 2 at the WSOP

Corkins Takes Down the Shorthanded Title with Doyle at his Side

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If you could only bring one person to sweat you in a World Series of Poker final table who would it be? Hoyt Corkins had a great answer…Doyle Brunson. "Texas Dolly" was on hand to watch as Alabama native and professional poker player Corkins took gold in event No. 30, $2,500 sixhanded no-limit hold'em. Corkins outlasted 847 players who created a $1,270,500 prize pool to take home the first-place prize of $515,065. Corkins came into the final table as the chip leader with $1,371,000, and the rest of the field stacked up as follows: Alan Sass ($1,217,000), William Pao-Wei Lin ($726,000), Terrence Chan ($502,000), Kelly Vande-Mheen ($307,000), and James Pittman ($127,000). Corkins built a dominating chip stack and used it to cut through the field.

He eventually got down to heads up with Chan, and he won his second bracelet on their 80th hand of play. Chan raised with A 4 on the button and Corkins shoved over the top. Chan thought for a few minutes, in a process that mirrored physical pain on several occasions. He wrestled with the dilemma then finally made the call. His pain suddenly subsided when he realized he was a favorite over Corkins' K 10. But the poker gods seemed to be with Corkins today, and the board came 9 8 8 K 6. Corkins won the pot and the tournament, relegating Chan to the second-place money, $287,345.

Corkins is an accomplished pro, and in addition to this victory, he won his first WSOP bracelet in 1992. Corkins also won a World Poker Tour title at Foxwoods in 2003. He also finished second in the 2005 WSOP Tournament of Champions. He is great friends with the Brunson family and often travels with them. Corkins took down $515,065 and his second coveted gold bracelet.